It is mandatory for all Chinese mobile phone makers to get the devices cleared by the Chinese telecommunications governing body TENAA before being released into the market. So, when a handset is cleared by the body, it is almost certain that it will be launched soon. Now, it has emerged that Xiaomi Mi Max has been certified by the same body.
The Chinese smartphone maker has announced that the Mi Max will be unveiled at the Beijing National Convention Centre on May 10. The device will be announced along with the new MIUI 8, a big update of Mi phones' operating system, and the Mi Band 2.
Xiaomi Mi Max has been cleared by TENAA, China's equivalent to the FCC, according to a report by TechUpdate (via Phone Arena) that quoted a Weibo post. It went on to say that the device would come with a price tag of 1,299 Yuan (around $199/Rs. 13,300).
The device was spotted at GFXBench site sporting a 6.4-inch full HD display with 1,920x1,080 pixels. Under the hood, it has a Qualcomm Snapdragon 650 processor, an Adreno 510, an Android 6.0.1 Marshmallow, 2GB RAM, 16GB internal memory, 16MP primary camera and a 5MP front-snapper.
Specifications of the device mentioned on TechUpdate are in sync with the ones seen on GFXBench. It claimed that the device will come in two variants, one with a 16GB internal storage and 2GB RAM, and the other with a 32GB internal storage and 3GB RAM (both with microSD card slot). It went on to say that the device will run MIUI 8 based on Android 6.0 Marshmallow, powered by a 4,000mAh battery and feature fingerprint sensor. In terms of connectivity, it is expected to support 4G LTE with VoLTE, Wi-Fi 802.11ac (2.4/5GHz), Bluetooth 4.1 and GPS + GLONASS.